A block B is pushed momentarily along a horiz | vedclass

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Question

Given $u = V$, final velocity $= 0$.
Using $v = u + at$

$\begin{array}{l}
	herefore \,0 = V - at\,\,or,\,\, - a = \frac{{0 - V}}{t} =  - \f

Vedclass · Accepted Answer

$\;\frac{V}{{g{\mu _k}}}$

Vedclass · Answer

Given $u = V$, final velocity $= 0$.
Using $v = u + at$

$\begin{array}{l}
	herefore \,0 = V - at\,\,or,\,\, - a = \frac{{0 - V}}{t} =  - \frac{V}{t}\
\,\,\,\,f = \mu R = \mu mg\,\left( {f\,is\,the\,force\,of\,friction} ight)\
	herefore {m{Retardation,}}\,{m{a}}\,{m{ = }}\mu {m{g}}\,	herefore {m{t}}\, = \frac{V}{a} = \frac{V}{{\mu g}}.
\end{array}$

A block $B$ is pushed momentarily along a horizontal surface with an initial velocity $V.$ If $\mu $ is the coefficient of sliding friction between $B$ and the surface, block $B$ will come to rest after a time

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