A block of mass 10 ,kg. moving with accelerat | vedclass

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Question

(a)

$a=2\,m / s ^2$

$g=9.8\,m / s ^2$

$Friction force = \mu g$

$=\mu 	imes 10 	imes 9.8$

$=98\,\mu$

Net force $=$ External force $

Vedclass · Accepted Answer

$0.2$

Vedclass · Answer

(a)

$a=2\,m / s ^2$

$g=9.8\,m / s ^2$

$Friction force = \mu g$

$=\mu 	imes 10 	imes 9.8$

$=98\,\mu$

Net force $=$ External force $=$ friction force

$m 	imes a =40-98\,\mu$

$2 	imes 10 =40-98\,\mu$

$98 \mu =40-20$

$=20$

$\mu=\frac{20}{98}=\frac{10}{49}=0.20$

A block of mass $10 \,kg$. moving with acceleration $2 \,m / s ^2$ on horizontal rough surface is shown in figure The value of coefficient of kinetic friction is ...........

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