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5.Work, Energy, Power and Collision
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A block is attached to a spring as shown and very-very gradually lowered so that finally spring expands by $"d"$. If same block is attached to spring & released suddenly then maximum expansion in spring will be-

A
$d$
B
$2\,d$
C
$3\,d$
D
$4\,d$
Solution
In first case acceleration of block is zero always.
therefore $\mathrm{mg}=\mathrm{kx}$
$\therefore \mathrm{x}=\frac{\mathrm{mg}}{\mathrm{k}}=\mathrm{d}(\mathrm{given})$
In second case block variably accelerate from rest
to rest
$0 =-\operatorname{mg} \mathrm{x}+\frac{1}{2} \mathrm{Kx}^{2}$
$\therefore \quad \mathrm{x} =\frac{2 \mathrm{mg}}{\mathrm{K}}=2 \mathrm{d}$
Standard 11
Physics
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