Gujarati
Hindi
5.Work, Energy, Power and Collision
medium

A block is attached to a spring as shown and very-very gradually lowered so that finally  spring expands by $"d"$. If same block is attached to spring & released suddenly then maximum expansion in spring will be-

A

$d$

B

$2\,d$

C

$3\,d$

D

$4\,d$

Solution

In first case acceleration of block is zero always.

therefore $\mathrm{mg}=\mathrm{kx}$

$\therefore \mathrm{x}=\frac{\mathrm{mg}}{\mathrm{k}}=\mathrm{d}(\mathrm{given})$

In second case block variably accelerate from rest
to rest

$0 =-\operatorname{mg} \mathrm{x}+\frac{1}{2} \mathrm{Kx}^{2}$

$\therefore \quad \mathrm{x} =\frac{2 \mathrm{mg}}{\mathrm{K}}=2 \mathrm{d}$

Standard 11
Physics

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