A block of mass $m$ lying on a rough horizontal plane is acted upon by a horizontal force $P$ and another force $Q$ inclined at an angle $\theta $ to the vertical. The block will remain in equilibrium, if the coefficient of friction between it and the surface is
- A$\frac{{(P + Q\sin \theta )}}{{(mg + Q\cos \theta )}}$
- B$\frac{{(P\cos \theta + Q)}}{{(mg - Q\sin \theta )}}$
- C$\frac{{(P + Q\cos \theta )}}{{(mg + Q\sin \theta )}}$
- D$\frac{{(P\sin \theta - Q)}}{{(mg - Q\cos \theta )}}$
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$(a)$ At what angle of inclination $\theta $ of the plane to the horizontal will the box just start to slide down the plane ?
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- [AIIMS 2001]
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