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9-1.Fluid Mechanics
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A block of steel of size $5 \times 5 \times 5 \,cm ^3$ is weighed in water. If relative density of steel is $7$ , its apparent weight is ........... $g wt$
A
$6 \times 5 \times 5 \times 5$
B
$4 \times 4 \times 4 \times 7$
C
$5 \times 5 \times 5 \times 7$
D
$4 \times 4 \times 4 \times 6$
Solution
(a)
Apparent weight $=\rho_s v_b g-\rho_w v_b g$
$=v_b g\left(\rho_s-\rho_w\right)$ $\left\{\begin{array}{l}\text { Where, } \\ \rho_s-\text { density of steel } \\ \rho_w-\text { density of water } \\ v_b-\text { volume of block }\end{array}\right.$
$=5 \times 5 \times 5 \times g \times(7-1)$ $\left[\begin{array}{l}\rho_w=1 \\ \rho_s=7\end{array}\right.$ (given)
$=6 \times 5 \times 5 \times 5 \times gwt$
Standard 11
Physics
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