A body cools from ${60^o}C$ to ${50^o}C$ in $10$ minutes when kept in air at ${30^o}C$. In the next $10$ minutes its temperature will be
Below ${40^o}C$
${40^o}C$
Above ${40^o}C$
Cannot be predicted
Two identical beakers $A$ and $B$ contain equal volumes of two different liquids at $60\,^oC$ each and left to cool down. Liquid in $A$ has density of $8 \times10^2\, kg / m^3$ and specific heat of $2000\, Jkg^{-1}\,K^{-1}$ while liquid in $B$ has density of $10^3\,kgm^{-3}$ and specific heat of $4000\,JKg^{-1}\,K^{-1}$ . Which of the following best describes their temperature versus time graph schematically? (assume the emissivity of both the beakers to be the same)
Which of the following statements is true/correct
Draw the graph that represents the cooling of hot water with time. Is the slope of the above graph positive or negative ?
A body initially at $80^o C$ cools to $64^o C$ in $5$ minutes and to $52^o C$ in $10 $ minutes. The temperature of the body after $15$ minutes will be ...... $^oC$
Ice is used in a cooler in order to cool its contents. Which of the following will speed up the cooling process?