Gujarati
2.Motion in Straight Line
easy

A body is moving according to the equation $x = at + b{t^2} - c{t^3}$ where $x = $ displacement and $a,\;b$ and $c$ are constants. The acceleration of the body is

A$a + 2bt$
B$2b + 6ct$
C$2b - 6ct$
D$3b - 6c{t^2}$

Solution

(c)$x = at + b{t^2} – c{t^3},\;a = \frac{{{d^2}x}}{{d{t^2}}} = 2b – 6ct$
Standard 11
Physics

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