A body is moving with a uniform acceleration | vedclass

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Question

$A$ to $\mathrm{B}: 40=\mathrm{u} 	imes 4+\frac{1}{2} \mathrm{a} 	imes 4^{2}$

$40=4 u+8 a$              $...(i

Vedclass · Accepted Answer

$0,\,\,5\,m/s^2$

Vedclass · Answer

$A$ to $\mathrm{B}: 40=\mathrm{u} 	imes 4+\frac{1}{2} \mathrm{a} 	imes 4^{2}$

$40=4 u+8 a$              $...(i)$

$A$ to $\mathrm{C}: 40+120=\mathrm{u} 	imes 8+\frac{1}{2} \mathrm{a} 	imes 8^{2}$

$160=8 u+32 a$               $...(ii)$

Solving $( i )$ and $(ii),$ we get

$\mathrm{u}=0, \mathrm{a}=5 \mathrm{m} / \mathrm{s}^{2}$

Colum $I$	Colum $II$
$(A)$ Change in velocity	$(p)$ $-5 / 3\,Sl$ unit
$(B)$ Average acceleration	$(q)$ $-20\,SI$ unit
$(C)$ Total displacement	$(r)$ $-10\,SI$ unit
$(D)$ Acceleration at $t=3\,s$	$(s)$ $-5\,SI$ unit

A body is moving with a uniform acceleration covers $40\,m$ in the first $4\,s$ and $120\,m$ in next $4\,s.$ Its initial velocity and acceleration are

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