A body is projected from the ground at an angle of $45^{\circ}$ with the horizontal. Its velocity after $2s$ is $20 \,ms ^{-1}$. The maximum height reached by the body during its motion is $m$. (use $g =10\, ms ^{-2}$ )
$20$
$25$
$29$
$200$
An arrow is shot into air. Its range is $200\,m$ and its time of flight is $5\,s$. If $g=10\,m / s ^2$, then horizontal component of velocity and the maximum height will be respectively
A ball is projected with kinetic energy $E$ at an angle of ${45^o}$ to the horizontal. At the highest point during its flight, its kinetic energy will be
Range of a bullet fired at $45^o$ to horizontal is $980m$. If the bullet is fired at same angle from a car travelling horizontally at $18\, km/hr$ towards target then range will be increased by :-
A particle of mass $m$ is projected with velocity $v$ making an angle of ${45^o}$with the horizontal. The magnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where $g = $ acceleration due to gravity)
A cricketer can throw a ball to a maximum horizontal distance of $100\, m$. The speed with which he throws the ball is ......... $ms^{-1}$ (to the nearest integer)