A body lying initially at point (3,7) starts moving with a constant acceleration of 4 hat{i} . Its p

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3-2.Motion in Plane

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A body lying initially at point $(3,7)$ starts moving with a constant acceleration of $4 \hat{i}$. Its position after $3 \,s$ is given by the co-ordinates ..........

A

$(7,3)$

B

$(7,18)$

C

$(21,7)$

D

$(3,7)$

Solution

(c)

The initial coordinate of the particle is $(3,7)$

$x$-coordinate is $3$ unit

$y$-coordinate is $7$ unit

As the body starts from rest so initial velocity $=0$

The acceleration of the body along $x$-axis $=4$ units

The acceleration of the body along $y$-axis $=0$

So, after $3$ seconds,

Using equation of motion along $x$-axis,

$x=x_0+u t+\frac{1}{2} a t^2$

as $u=0 \quad a=4$ units $\quad t=3$ seconds

$s=3+\frac{1}{2} \times 4 \times 3^2=2$ lunits

As there is no motion along $y$-axis so it will remain unchanged

Hence the final coordinate are $(21,7)$

Standard 11

Physics

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