Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

A body moving with speed $v$ in space explodes into two piece of masses in the ratio $1 : 3.$ If the smaller piece comes to rest, the speed of the other piece is

A

$4v$

B

$v$

C

$\frac{4v}{3}$

D

$\frac{3v}{4}$

Solution

$\mathrm{mu}=\mathrm{m}_{1} \mathrm{v}_{1}+\mathrm{m}_{2} \mathrm{v}_{2}$

$\mathrm{mv}=0+\frac{3}{4} \mathrm{mv}_{2} \Rightarrow \mathrm{v}_{2}=\frac{4 \mathrm{v}}{3}$

Standard 11
Physics

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