Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

A body of mass $8\,kg$ is hanging another body of mass $12\,kg$. The combination is being pulled by a string $T _2$ will be respectively: (use $g =9.8\,m / s ^2$ )

A

$240\,N , 96\,N$

B

$200\,N , 80\,N$

C

$220\,N ,90\,N$

D

$260\,N ,96\,N$

Solution

$T_2-80=8(2.2) \ldots(1)$

$T_1^2-T_2-120=12(2.2) \quad \ldots(2)$

$\text { After solving (1) to }(2) \quad\left[\text { take } g=9.8\,m / s ^2\right]$

$T _1=240\,N$

$T _2=96\,N$

Standard 11
Physics

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