A body of mass $m$ is moving in a circle of radius $r$ with a constant speed $u$. The force on the body is $mv^2/r$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle?
A body of mass $m$ is moving in a circle of radius $r$ with a constant speed $u$. The force on the body is $mv^2/r$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle?
- A
$\frac {mv^2}{r}\,\times \pi r$
- B
zero
- C
$\frac {mv^2}{r}$
- D
$\frac {\pi r^2}{mv^2}$
Similar Questions
A particle of mass $m$ strikes the ground inelastically, with coefficient of restitution $e$
A particle of mass $m$ strikes the ground inelastically, with coefficient of restitution $e$
$F = 2x^2 - 3x - 2$. Choose correct option
$F = 2x^2 - 3x - 2$. Choose correct option
A batsman hits a sixer and the ball touches the ground outside the cricket ground. Which of the following graph describes the variation of the cricket ball's vertical velocity $v$ with time between the time ${t_1}$ as it hits the bat and time $t_2$ when it touches the ground
A batsman hits a sixer and the ball touches the ground outside the cricket ground. Which of the following graph describes the variation of the cricket ball's vertical velocity $v$ with time between the time ${t_1}$ as it hits the bat and time $t_2$ when it touches the ground
If the kinetic energy of a body is directly proportional to time $t$, the magnitude of force acting on the body is
$(i)$ directly proportional to $\sqrt t$
$(ii)$ inversely proportional to $\sqrt t$
$(iii)$ directly proportional to the speed of the body
$(iv)$ inversely proportional to the speed of body
If the kinetic energy of a body is directly proportional to time $t$, the magnitude of force acting on the body is
$(i)$ directly proportional to $\sqrt t$
$(ii)$ inversely proportional to $\sqrt t$
$(iii)$ directly proportional to the speed of the body
$(iv)$ inversely proportional to the speed of body
The total work done on a particle is equal to the change in its kinetic energy. This is applicable
The total work done on a particle is equal to the change in its kinetic energy. This is applicable