A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M . If block rise

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5.Work, Energy, Power and Collision

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A bullet of mass $m$ moving with velocity $v$ strikes a suspended wooden block of mass $M$. If the block rises to a height $h$, the initial velocity of the bullet will be

A

$\frac{{m + M}}{m}\sqrt {2gh} $

B

$\sqrt {2gh} $

C

$\frac{{M + m}}{M}\sqrt {2gh} $

D

$\frac{m}{{M + m}}\sqrt {2gh} $

Solution

$mv = (m + M)V$

$V = \sqrt {2gh} $

$mv = (m + M)\sqrt {2gh} $

==> $v = \frac{{m + M}}{m}\sqrt {2gh} $.

Standard 11

Physics

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