4-1.Newton's Laws of Motion
medium

A body of mass $5 \,kg$  explodes at rest into three fragments with masses in the ratio $1 : 1 : 3$. The fragments with equal masses fly in mutually perpendicular directions with speeds of $21 \,m/s$. The velocity of the heaviest fragment will be

A

$3\sqrt 2\;m/s$

B

$5\sqrt 2\;m/s$

C

$\sqrt 2\;m/s$

D

$7\sqrt 2\;m/s$

(AIPMT-1989)

Solution

(d)${P_x} = m \times {v_x} = 1 \times 21 = 21\;kg\;m/s$

${P_y} = m \times {v_y} = 1 \times 21 = 21\;kg\;m/s$

Resultant =$\sqrt {P_x^2 + P_y^2} = 21\sqrt 2 $kg m/s

The momentum of heavier fragment should be numerically equal to resultant of ${\vec P_x}$ and ${\vec P_y}$.

$3 \times v = \sqrt {P_x^2 + P_y^2} = 21\sqrt 2 $ $v = 7\sqrt 2 $

$= 9.89 \,m/s$

Standard 11
Physics

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