7.Gravitation
medium

A body of mass $m$ is placed on the earth’s surface. It is taken from the earth’s surface to a height $h = 3R$. The change in gravitational potential energy of the body is

A

$\frac{2}{3}mgR$

B

$\frac{3}{4}mgR$

C

$\frac{{mgR}}{2}$

D

$\frac{{mgR}}{4}$

(AIPMT-2002)

Solution

(b) $\Delta U = \frac{{mgh}}{{1 + \frac{h}{R}}} = \frac{{mg \times 3R}}{{1 + \frac{{3R}}{R}}} = \frac{3}{4}mgR$

Standard 11
Physics

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