Gujarati
2.Motion in Straight Line
easy

A body of mass $10\, kg$ is moving with a constant velocity of $10 \,m/s$. When a constant force acts for $4 \,seconds$ on it, it moves with a velocity $2 \,m/sec$ in the opposite direction. The acceleration produced in it is...........$m/{\sec ^2}$

A

$3$

B

$ - 3$

C

$0.3$

D

$ - 0.3$

Solution

(b) $v = u + at$ $ \Rightarrow – 2 = 10 + a \times 4$ $ \Rightarrow a = – 3m/se{c^2}$

Standard 11
Physics

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