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3-2.Motion in Plane
normal
A body of mass $m\, kg$ is rotating in a vertical circle at the end of a string of length $r$ metre. The difference in the kinetic energy at the top and the bottom of the circle is
A
$\frac{{mg}}{r}$
B
$\frac{{2mg}}{r}$
C
$2mgr$
D
$mgr$
Solution
(c) Difference in $K.E.$ = Difference in $P.E.$ = $2mgr$
Standard 11
Physics