Gujarati
3-2.Motion in Plane
normal

A body of mass $m\, kg$ is rotating in a vertical circle at the end of a string of length $r$ metre. The difference in the kinetic energy at the top and the bottom of the circle is

A

$\frac{{mg}}{r}$

B

$\frac{{2mg}}{r}$

C

$2mgr$

D

$mgr$

Solution

(c) Difference in $K.E.$ = Difference in $P.E.$ = $2mgr$

Standard 11
Physics

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