A body of mass 0.5 ,kg is projected under gravity with a speed of 98 ,m/s at an angle of {30^o} with

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3-2.Motion in Plane

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A body of mass $0.5 \,kg$ is projected under gravity with a speed of $98 \,m/s$ at an angle of ${30^o}$ with the horizontal. The change in momentum (in magnitude) of the body is ......... $N-s$

A

$24.5$

B

$49$

C

$98$

D

$50$

Solution

(b) Change in momentum = $2mu\sin \theta $

$=2 \times 0.5 \times 98 \times \sin 30=49N{\rm{ – }}s$

Standard 11

Physics

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