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3-2.Motion in Plane
medium
Two projectiles are thrown simultaneously in the same plane from the same point. If their velocities are $v_1$ and $v_2$ at angles $\theta _1$ and $\theta_2$ respectively from the horizontal, then answer the following question
The trajectory of particle $1$ with respect to particle $2$ will be
Aa parabola
Ba straight line
Ca vertical straight line
Da horizontal straight line
Solution
$V_{12(x)}=v_{1} \cos \theta_{1}-v_{2} \cos \theta_{2}$
$a_{12(x)}=0 \Rightarrow V_{12(y)}-V_{1} \sin _{1}^{\theta}-V_{2} \sin ^{\theta}_{2}$
$\Rightarrow a_{12(y)}=0$
$x=v_{12(x)} t \ldots(1)$
$y=v_{12(y)} t \ldots(2)$
From $(1) \&(2) Y=\frac{V_{12}(y)}{V_{12(y)}}$
$a_{12(x)}=0 \Rightarrow V_{12(y)}-V_{1} \sin _{1}^{\theta}-V_{2} \sin ^{\theta}_{2}$
$\Rightarrow a_{12(y)}=0$
$x=v_{12(x)} t \ldots(1)$
$y=v_{12(y)} t \ldots(2)$
From $(1) \&(2) Y=\frac{V_{12}(y)}{V_{12(y)}}$
Standard 11
Physics
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