A body of mass m rises to height h = R/5 from earth's surface, where R is earth's radius. If

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7.Gravitation

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A body of mass m rises to height $h = R/5$ from the earth's surface, where $R$ is earth's radius. If $g$ is acceleration due to gravity at earth's surface, the increase in potential energy is

A

$mgh$

B

$\frac{4}{5}mgh$

C

$\frac{5}{6}mgh$

D

$\frac{6}{7}mgh$

Solution

(c) $\Delta U = \frac{{mgh}}{{1 + h/R}}$

Substituting $R = 5h$ we get $\Delta U = \frac{{mgh}}{{1 + 1/5}} = \frac{5}{6}mgh$

Standard 11

Physics

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