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6.System of Particles and Rotational Motion
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A body rolls down an inclined plane without slipping. The kinetic energy of rotation is $50 \,\%$ of its translational kinetic energy. The body is :
A
Solid sphere
B
Solid cylinder
C
Hollow cylinder
D
Ring
(JEE MAIN-2021)
Solution
$\frac{1}{2} I \omega^{2}=\frac{1}{2} \times \frac{1}{2} m v^{2}$
$v=\omega R$
$I=\frac{1}{2} m R^{2}$
Body is solid cylinder
Standard 11
Physics
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