A body rolls down an inclined plane without slipping. kinetic energy of rotation is 50 ,% of its tra

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6.System of Particles and Rotational Motion

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A body rolls down an inclined plane without slipping. The kinetic energy of rotation is $50 \,\%$ of its translational kinetic energy. The body is :

A

Solid sphere

B

Solid cylinder

C

Hollow cylinder

D

Ring

(JEE MAIN-2021)

Solution

$\frac{1}{2} I \omega^{2}=\frac{1}{2} \times \frac{1}{2} m v^{2}$

$v=\omega R$

$I=\frac{1}{2} m R^{2}$

Body is solid cylinder

Standard 11

Physics

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