One end of rod of length $L$ is on horizontal plane. It is inclined at angle $\alpha$ to horizontal plane. When released its angular velocity after coming to horizontal plane is
$\sqrt{\frac{3g \sin \alpha}{L}}$
$\sqrt{\frac{2L}{3g \sin \alpha}}$
$\sqrt{\frac{6g \sin \alpha}{L}}$
$\sqrt{\frac{L}{g \sin \alpha}}$
Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities $\omega_1$ and $\omega_2$ They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is
A disc and a ring of same mass are rolling and if their kinetic energies are equal, then the ratio of their velocities will be
A circular disc of moment of inertia $I_t$, is rotating in a horizontal plane, about its symmetry axis, with a constant angular speed $\omega_i$ . Another disc of moment of inertia $l_b$ is dropped coaxially onto the rotating disc. Initially the second disc has zero angular speed. Eventually both the discs rotate with a constant angular speed $\omega_f$. The energy lost by the initially rotating disc to friction is
A solid cylinder length is suspended symmetrically through two massless strings, as shown in the figure. The distance from the initial rest position, the cylinder should by unbinding the strings to achieve a speed of $4\,ms ^{-1}$, is$........cm$. $\left(\right.$ take $\left.g=10\,ms ^{-2}\right)$
A thin hollow cylinder open at both ends:
$(i)$ Slides without rotating
$(ii)$ Rolls without slipping, with the same speed