Initial velocity of particle is 10,m/sec and its retardation is 2m/sec^2 . distance moved by particl

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2.Motion in Straight Line

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The initial velocity of the particle is $10\,m/\sec $ and its retardation is $ 2\;m/sec^2$. The distance moved by the particle in $5^{th}$ second of its motion is..........$m$

A$1$

B$19$

C$50$

D$75$

Solution

(a) ${S_n} = u – \frac{a}{2}(2n – 1)$ $ = 10 – \frac{2}{2}(2 \times 5 – 1) = 1\;meter$

Standard 11

Physics

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