10-2.Transmission of Heat
medium

A body takes $5$ minutes to cool from $90^oC$ to $60^oC$. If the temperature of the surroundings is $20^oC$, the time taken by it to cool from $60^oC$ to $30^oC$ will be ...... $\min.$

A

$5$

B

$8$

C

$11$

D

$12$

Solution

(c) $\frac{{90 – 60}}{5} = k\left( {\frac{{90 + 60}}{2} – 20} \right)$

==> $6 = k \times 55$

==> $K = \frac{6}{{55}}$
And, $\frac{{60 – 30}}{t} = \frac{6}{{55}}\left( {\frac{{60 + 30}}{2} – 20} \right)$

==> $t = 11 minute$.

Standard 11
Physics

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