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2.Motion in Straight Line
hard
એક પદાર્થ ${n}^{\text {th }}$ સેકંડમાં $102.5 {~m}$ અને $(n+2)^{\text {th }}$ સેકંડમાં $115.0 \mathrm{~m}$ મુસાફરી કરે છે. તેનો પ્રવેગ શું છે?
A $9 \mathrm{~m} / \mathrm{s}^2$
B$6.25 \mathrm{~m} / \mathrm{s}^2$
C$12.5 \mathrm{~m} / \mathrm{s}^2$
D$5 \mathrm{~m} / \mathrm{s}^2$
(JEE MAIN-2024)
Solution
Given, $102.5=\mathrm{u}+\frac{\mathrm{a}}{2}(2 \mathrm{n}-1) \&$
$115=\mathrm{u}+\frac{\mathrm{a}}{2}(2 \mathrm{n}+3)$
$\Rightarrow 102.5=\mathrm{u}+\mathrm{an}-\frac{\mathrm{a}}{2} \&$
$115=\mathrm{u}+\mathrm{an}+\frac{3 \mathrm{a}}{2}$
$12.5=2 \mathrm{a} \Rightarrow \mathrm{a}=6.25 \mathrm{~m} / \mathrm{s}^2$
Hence option $(2)$
$115=\mathrm{u}+\frac{\mathrm{a}}{2}(2 \mathrm{n}+3)$
$\Rightarrow 102.5=\mathrm{u}+\mathrm{an}-\frac{\mathrm{a}}{2} \&$
$115=\mathrm{u}+\mathrm{an}+\frac{3 \mathrm{a}}{2}$
$12.5=2 \mathrm{a} \Rightarrow \mathrm{a}=6.25 \mathrm{~m} / \mathrm{s}^2$
Hence option $(2)$
Standard 11
Physics
