A body weighs 72, N on surface of earth. gravitational force(in N ) on it, at a helght equal to half

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7.Gravitation

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A body weighs $72\, N$ on the surface of the earth. What is the gravitational force(in $N$) on it, at a helght equal to half the radius of the earth$?$

A

$24$

B

$48$

C

$32$

D

$30$

Solution

$W_{s}=m g_{s}=72 N$

$W_{h}=m g_{h}=\frac{m g_{s}}{\left(1+\frac{h}{R}\right)^{2}}=\frac{72 N}{\left(1+\frac{R / 2}{R}\right)^{2}}=\frac{72}{9 / 4}$

$W_{h}=32 N$

Standard 11

Physics

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