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5.Work, Energy, Power and Collision
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A bomb of mass $9\, kg$ explodes into two pieces of masses $3\, kg$ and $6\, kg$. The velocity of mass $3\, kg$ is $16\, m/s$. The $KE$ of mass $6\, kg$ (in joule) is
A
$96$
B
$384$
C
$192$
D
$768$
Solution
$3 \times 16=6 \times V$
$\mathrm{V}=8 \mathrm{m} / \mathrm{s}$
$\mathrm{KE}$ of $6 \mathrm{kg}$ mass $=\frac{1}{2} \times 6 \times 8^{2}=192 \mathrm{J}$
Standard 11
Physics
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