Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

A bomb of mass $9\, kg$ explodes into two pieces of masses $3\, kg$ and $6\, kg$. The velocity of mass $3\, kg$ is $16\, m/s$. The $KE$ of mass $6\, kg$ (in joule) is

A

$96$

B

$384$

C

$192$

D

$768$

Solution

$3 \times 16=6 \times V$

$\mathrm{V}=8 \mathrm{m} / \mathrm{s}$

$\mathrm{KE}$ of $6 \mathrm{kg}$ mass $=\frac{1}{2} \times 6 \times 8^{2}=192 \mathrm{J}$

Standard 11
Physics

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