A bullet fired into a fixed target loses half of its velocity after penetrating 3, cm . How&nbs

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2.Motion in Straight Line

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A bullet fired into a fixed target loses half of its velocity after penetrating $3\, cm$. How much further will it penetrate before coming to rest assuming that it faces constant resistance to motion.........$cm$

A

$1.5$

B

$1$

C

$3$

D

$2$

Solution

$\left(\frac{\mathrm{V}}{2}\right)^{2}=\mathrm{V}^{2}-2 \mathrm{a}(3)$ $…(1)$

$0^{2}=\mathrm{V}^{2}-2 \mathrm{a}(\mathrm{S})$ $…(2)$

Solving $\mathrm{S}=4 \mathrm{cm}$

So, $4-3=1 \mathrm{cm}$

Standard 11

Physics

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