A car moving along a straight highway with speed of $126 \;\mathrm{km} h^{-1}$ is brought to a stop within a distance of $200\; \mathrm{m}$. how long(in $seconds$) does it take for the car to stop?
$u=126 \mathrm{km} / \mathrm{h}=126 \times \frac{5}{18} \mathrm{m} / \mathrm{s}=35 \mathrm{m} / \mathrm{s}$
$v=0$
$s=200 m$
Newton's Equation of motion $v^{2}-u^{2}=2 a s$
$0^{2}-35^{2}=2 a(200)$
$a=-3.0625 \mathrm{m} / \mathrm{s}^{2}$
Also
$v=u+a t$
$0=35-3.06 t$
$t=11.4 \;s$
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On what factors, does the stopping distance depend ?
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