A bullet fired into a fixed target loses half of its velocity after penetrating 3,cm . How much furt

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2.Motion in Straight Line

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A bullet fired into a fixed target loses half of its velocity after penetrating $3\,cm$ . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?.......$cm$

A

$4$

B

$1$

C

$3$

D

$2$

Solution

$\mathrm{V}_{f}^{2}-\mathrm{V}_{i}^{2}=-2 \mathrm{a}[3]$

$\frac{V^{2}}{4}-V^{2}=-2 a(3)$ $…(1)$

$0-\mathrm{V}^{2}=-2 \mathrm{a}(\mathrm{x})$ $…(2)$

$(1)$ $/(2)$

$\frac{\frac{3 V^{2}}{4}}{V^{2}}=\frac{3}{x}$

${\mathrm{x}=4 \mathrm{cm}}$

Extra $=4-3=1 \mathrm{cm}$

Standard 11

Physics

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