The velocity-time graphs of a car and a scoot | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\begin{array}{l}
{m{Using}}\,equation,\,a = \frac{{v - u}}{t}\,and\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,

Vedclass · Accepted Answer

$112.5\,m$ અને $22.5\,s$

Vedclass · Answer

$\begin{array}{l}
{m{Using}}\,equation,\,a = \frac{{v - u}}{t}\,and\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,s = ut + \frac{1}{2}a{t^2}\
{m{Distance}}\,{m{travelled}}\,{m{by}}\,{m{car}}\,{m{in}}\,{m{15}}\,{m{sec}}\
{m{ = }}\frac{1}{2}\frac{{\left( {45} ight)}}{{15}}{\left( {15} ight)^2}\
 = \frac{{675}}{2}\,m\
{m{Distance}}\,{m{traveled}}\,{m{by}}\,{m{scooter}}\,{m{in}}\,{m{15}}\,{m{seconds}}
\end{array}$

$\begin{array}{l}
{m{ = 30}} 	imes 15 = 450\left( {{m{distance}} = speed 	imes time} ight)\
Difference\,between\,{m{distance}}\,travelled\,by\,car\
and\,scooter\,in\,15\,\sec ,\,450 - 337.5 = 112.5\,m\
Let\,car\,catches\,scooter\,in\,time\,t;\
\frac{{675}}{2} + 45\left( {t - 15} ight) = 30t\
337.5 + 45t - 675 = 30t\
 \Rightarrow \,15t = 337.5\
 \Rightarrow \,t = 22.5\,\sec 
\end{array}$

The velocity-time graphs of a car and a scooter are shown in the figure. $(i)$ the difference between the distance travelled by the car and the scooter in $15\, s$ and $(ii)$ the time at which the car will catch up with the scooter are, respectively

Similar Questions

The velocity $(v)-$ time $(t)$ plot of the motion of a body is shown below:

(image)

The acceleration $(a)-$ time $(t)$ graph that best suits this motion is :

Two points move in the same straight line starting at the same moment from the same point in it. The first moves with constant velocity $u$ and the second with constant acceleration $f$. During the time elapses before the second catches, the first greatest distance between the particle is $........$

The $x$ and $y$ coordinates of a particle at any time $t$ are given by $x = 7t + 4{t^2}$ and $y = 5t$, where $x$ and $y$ are in metre and $t$ in seconds. The acceleration of particle at $t = 5\;s$ is.........$m/{s^2}$

Equation of displacement for any particle is $s = 3{t^3} + 7{t^2} + 14t + 8m$. Its acceleration at time $t = 1\, sec $ is.......$ms^{-2}$

The acceleration-time graph for a particle moving along $x$-axis is shown in figure. If the initial velocity of particle is $-5 \,m / s$, the velocity at $t=8 \,s$ is ....... $m / s$