A bullet of mass m moving with a speed v strikes a wooden block of mass M and gets embedded into blo

English

Gujarati

Hindi

5.Work, Energy, Power and Collision

normal

A bullet of mass $m$ moving with a speed $v$ strikes a wooden block of mass $M$ and gets embedded into the block. The final speed is

A

$\sqrt {\frac{M}{{M + m}}} v$

B

$\sqrt {\frac{m}{{M + m}}} v$

C

$\frac{m}{{M + m}}v$

D

$\frac {v}{2}$

Solution

$mv\, = \,\left( {M + m} \right){v_f}$

$\therefore \,\,{v_f} = \frac{m}{{M + m}}v$

Standard 11

Physics

Share

Similar Questions

Power applied to a particle varies with time as $P = [3t^2 -2t + 1]$ $watt$ then the change in kinetic energy of particle from $t = 2\,sec$ to $t = 4\,sec.$ …………… $\mathrm{J}$

normal

A uniform chain of length $2\, m$ is kept on a table such that a length of $60\, cm$ hangs freely from the edge of the table. The total mass of the chain is $4\, kg$. What is the work done in pulling the entire chain on the table ? ……………. $\mathrm{J}$

normal

Work equal to $25\,J$ is done on a mass of $2\,kg$ to set it in motion. If whole of it is used to increase the kinetic energy then velocity acquired by the mass is ………… $\mathrm{m}/ \mathrm{s}$

normal

A mass $m$ moving horizontally with velocity $v_0$ strikes a pendulum of mass $m$. If the two masses stick together after the collision, then the maximum height reached by the pendulum is

normal

Figure shows the vertical section of frictionless surface. A block of mass $2\, kg$ is released from the position $A$ ; its $KE$ as it reaches the position $C$ is ………… $\mathrm{J}$

normal