A bullet of mass 40 ,g is fired from a gun of mass 10 ,kg . If velocity of bullet is 400 ,m / s , th

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4-1.Newton's Laws of Motion

easy

A bullet of mass $40 \,g$ is fired from a gun of mass $10 \,kg$. If velocity of bullet is $400 \,m / s$, then the recoil velocity of the gun will be ..........

A

$1.6 \,m / s$ in the direction of bullet

B

$1.6 \,m / s$ opposite to the direction of bullet

C

$1.8 \,m / s$ in the direction of bullet

D

$1.8 \,m / s$ opposite to the direction of bullet

Solution

(b)

Using conservation of momentum

$p_i=P_f$

$P_i=0$

$P_f=\frac{40}{1000}(400)+10 v$

So in $(i)$

$o=\frac{40}{1000}(400)+10 v$

$v=-1.6 \,m / s$

Standard 11

Physics

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