A bullet of mass 0.1,kg moving horizontally w | vedclass

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Question

$P _{ i }= P _{ f }(	ext { Collision })$

$\Rightarrow(0.1)(400)=(0.1+3.9) v$

$\Rightarrow v =\frac{0.1 	imes 400}{4}=10\,m / s$

$a =\frac{\

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

$P _{ i }= P _{ f }(	ext { Collision })$

$\Rightarrow(0.1)(400)=(0.1+3.9) v$

$\Rightarrow v =\frac{0.1 	imes 400}{4}=10\,m / s$

$a =\frac{\mu mg }{ m }=\mu g$

Apply equation of motion,

$v ^2=u^2+2 as$

$\Rightarrow 0=(10)^2-2 \mu g 	imes 20$

$\Rightarrow 40 \mu g =100$

$\Rightarrow \mu=\frac{100}{2 	imes 10 	imes 20}=\frac{1}{4}$

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