2. Electric Potential and Capacitance
easy

A bullet of mass $2\, gm$ is having a charge of $2\,\mu C$. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of $10\,m/s$

A

$5\, kV$

B

$50\, kV$

C

$5\, V$

D

$50\, V$

(AIPMT-2004)

Solution

(b) By using $\frac{1}{2}m{v^2} = QV$

$==>$ $\frac{1}{2} \times 2 \times {10^{ – 3}} \times {(10)^2} = 2 \times {10^{ – 6}}\,V$

$==>$ $V = 50\,kV$

Standard 12
Physics

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