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2. Electric Potential and Capacitance
easy
A bullet of mass $2\, gm$ is having a charge of $2\,\mu C$. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of $10\,m/s$
A
$5\, kV$
B
$50\, kV$
C
$5\, V$
D
$50\, V$
(AIPMT-2004)
Solution
(b) By using $\frac{1}{2}m{v^2} = QV$
$==>$ $\frac{1}{2} \times 2 \times {10^{ – 3}} \times {(10)^2} = 2 \times {10^{ – 6}}\,V$
$==>$ $V = 50\,kV$
Standard 12
Physics
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