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Question

$v_{1}=50 km / hr$ due north

$v_{2}=50 km / hr 	ext { due west }$

$-v_{1}=50 km / hr 	ext { due south }$

Magnitude of change in velocity

Vedclass · Accepted Answer

$70.7 \;km / hr$ along south-west direction

Vedclass · Answer

$v_{1}=50 km / hr$ due north

$v_{2}=50 km / hr 	ext { due west }$

$-v_{1}=50 km / hr 	ext { due south }$

Magnitude of change in velocity

$=\left|\vec{v}_{2}-\vec{v}_{1}ight|=\left|\vec{v}_{2}+\left(-\vec{v}_{1}ight)ight|$

$=\sqrt{v_{2}^{2}+\left(-v_{1}ight)^{2}}$

$=\sqrt{(50)^{2}+(50)^{2}}=70.7 km / hr$

$\vec{v}=70.7 km / hr$ along south-west direction

A bus is moving on a straight road towards north with a uniform speed of $50\; km / hour$ then it turns left through $90^{\circ} .$ If the speed remains unchanged after turning, the increase in the velocity of bus in the turning process is

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