A cannon on a level plane is aimed at an angle $\theta $ above the horizontal and a shell is fired with a muzzle velocity ${v_0}$ towards a vertical cliff a distance $D$ away. Then the height from the bottom at which the shell strikes the side walls of the cliff is
$D\sin \theta - \frac{{g{D^2}}}{{2v_0^2{{\sin }^2}\theta }}$
$D\cos \theta - \frac{{g{D^2}}}{{2v_0^2{{\cos }^2}\theta }}$
$D\tan \theta - \frac{{g{D^2}}}{{2v_0^2{{\cos }^2}\theta }}$
$D\tan \theta - \frac{{g{D^2}}}{{2v_0^2{{\sin }^2}\theta }}$
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is ......... $^o$
Two projectiles are thrown simultaneously in the same plane from the same point. If their velocities are $v_1$ and $v_2$ at angles $\theta _1$ and $\theta_2$ respectively from the horizontal, then answer the following question
If $v_1\,\,sin\,\,\theta _1 = v_2\,\,sin\,\,\theta _2$, then choose the incorrect statement
An object is projected with a velocity of $20 m/s$ making an angle of $45^o$ with horizontal. The equation for the trajectory is $h = Ax -Bx^2$ where $h$ is height, $x$ is horizontal distance, $A$ and $B$ are constants. The ratio $A : B$ is ($g = 10 ms^{-2}$)
The equation of a projectile is $y=\sqrt{3} x-\frac{ x^2}{2}$, the velocity of projection is
A piece of marble is projected from earth's surface with velocity of $19.6 \sqrt{2}\,m / s$ at $45^{\circ}.$ $2\,s$ later its velocity makes an angle $\alpha$ with horizontal, where $\alpha$ is $..........$