A capacitor of capacitance $C_0$ is charged to a potential $V_0$ and is connected with another capacitor of capacitance $C$ as shown. After closing the switch $S$, the common potential across the two capacitors becomes $V$. The capacitance $C$ is given by
A capacitor of capacitance $C_0$ is charged to a potential $V_0$ and is connected with another capacitor of capacitance $C$ as shown. After closing the switch $S$, the common potential across the two capacitors becomes $V$. The capacitance $C$ is given by
- A
$\frac{{{C_0}\left( {{V_0} - V} \right)}}{{{V_0}}}$
- B
$\frac{{{C_0}\left( {V - {V_0}} \right)}}{{{V_0}}}$
- C
$\frac{{{C_0}\left( {V + {V_0}} \right)}}{V}$
- D
$\frac{{{C_0}\left( {{V_0} - V} \right)}}{V}$
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