A capacitor of capacitance 500,μ F is charged completely using a dc supply of 100,V . It is now con

English

Gujarati

Hindi

7.Alternating Current

medium

A capacitor of capacitance $500\,\mu F$ is charged completely using a dc supply of $100\,V$. It is now connected to an inductor of inductance $50\,mH$ to form an $LC$ circuit. The maximum current in $LC$ circuit will be $.........A$.

A

$10$

B

$1$

C

$0$

D

$100$

(JEE MAIN-2022)

Solution

Energy stored in capacitor

$=\frac{1}{2} CV ^{2}=\frac{1}{2} 500 \times 10^{-6} \times 10^{4}$

$=\frac{5}{2}\,J$

Current will be maximum when whole energy of capacitor becomes energy of inductor.

$\frac{1}{2} LI ^{2}=\frac{5}{2}$

$I =\sqrt{\frac{5}{ L }}=\sqrt{\frac{5}{50 \times 10^{-3}}}=10\,A$

Standard 12

Physics

Share

Similar Questions

Let $f = 50\, Hz$, and $C = 100\, \mu\, F$ in an $AC$ circuit containing a capicator only. If the peak value of the current in the circuit is $1.57$ $A$ at $t = 0$. The expression for the instantaneous voltage across the capacitor will be

hard

An $LR$ circuit with a battery is connected at $t = 0$. Which of the following quantities is not zero just after the circuit

medium

In figure, the switch $S$ is closed so that a current flows in the iron-core inductor which has inductance $L$ and the resistance $R$. When the switch is opened, $a$ spark is obtained in it at the contacts. The spark is due to

medium

A $120\, volt$ $ac$ source is connected across a pure inductor of inductance $0.70 \,henry.$ If the frequency of the source is $60\, Hz$, the current passing through the inductor is

easy

When an ac source of $e.m.f.\ e = E_0 sin(100t)$ is connected across a circuit, the phase difference between the $e.m.f.\ e$ and the current $i$ in the circuit is observed to be $\frac{\pi }{4}$ as shown in the diagram. If the circuit consists possibly only of $ RC$ or $ RL $ or $ LC$ in series, find the relationship between the two elements

hard