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2. Electric Potential and Capacitance
easy
A capacitor of capacitance $6\,\mu \,F$ is charged upto $100$ $volt$. The energy stored in the capacitor is........$Joule$
A
$0.6$
B
$0.06$
C
$0.03$
D
$0.3$
Solution
(c) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 6 \times {10^{ – 6}}{(100)^2} = 0.03\,J$
Standard 12
Physics