Gujarati
2. Electric Potential and Capacitance
easy

capacitor is used to store $24\, watt\, hour$ of energy at $1200\, volt$. What should be the capacitance of the capacitor

A

$120\,m\,F$

B

$120\,\mu \,F$

C

$24\,\mu \,F$

D

$24\,m\,F$

Solution

(a) $U = \frac{1}{2}C{V^2}$   

so $24 \times 60 \times 60 = \frac{1}{2}C{(1200)^2}$

$⇒ C=120 \,mF$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.