A car goes around uniform circular track of r | vedclass

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Question

(c)

When car goes around track of radius $R$, then

Time period, $\quad T=\frac{2 \pi R}{v}$

Centripetal acceleration, $a_c=\frac{v^2}{R}$

Vedclass · Accepted Answer

$T / 2$

Vedclass · Answer

(c)

When car goes around track of radius $R$, then

Time period, $\quad T=\frac{2 \pi R}{v}$

Centripetal acceleration, $a_c=\frac{v^2}{R}$

When car goes around circular track of radius $2 R$, then

Centripetal acceleration,

$a_c^{\prime}=\frac{v^{\prime 2}}{2 R}=\frac{8 v^2}{R} \Rightarrow v^{\prime}=4 v$

So, time period of car is

$T^{\prime}=\frac{2 \pi R^{\prime}}{v^{\prime}}=2 \pi(2 R)$

$=\frac{1}{2} 	imes \frac{2 \pi R}{v}=\frac{T}{2}$

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