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4-1.Newton's Laws of Motion
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A car of mass $1000\,kg$ negotiates a banked curve of radius $90\,m$ on a frictionless road. If banking angle is $45^o$ , the maximum speed of car is ............ $m/s$ $[g = 10\,m/s^2]$
A$20$
B$30$
C$5$
D$10$
Solution
$\tan \theta=\frac{\mathrm{v}^{2}}{\mathrm{Rg}}$
$\tan 45^{\circ}=\frac{\mathrm{v}^{2}}{90 \times 10}$
$\mathrm{v}=\sqrt{900}=30 \mathrm{m} / \mathrm{s}$
$\tan 45^{\circ}=\frac{\mathrm{v}^{2}}{90 \times 10}$
$\mathrm{v}=\sqrt{900}=30 \mathrm{m} / \mathrm{s}$
Standard 11
Physics
