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4.Moving Charges and Magnetism
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A car of mass $1000\,kg$ negotiates a banked curve of radius $90\,m$ on a fictionless road. If the banking angle is $45^o$, the speed of the car is ......... $ms^{-1}$
A
$5$
B
$10$
C
$20$
D
$30$
Solution
$\tan \theta=\frac{\mathrm{v}^{2}}{\mathrm{rg}} \Rightarrow \mathrm{v}=\sqrt{\mathrm{rg} \tan \theta}=\sqrt{90 \times 10 \times \tan 45}$
$\mathrm{v}=30 \mathrm{m} / \mathrm{s}$
Standard 12
Physics