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4.Moving Charges and Magnetism
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A proton and an alpha particle of the same enter in a uniform magnetic field which is acting perpendicular to their direction of motion. The ratio of the circular paths described by the alpha particle and proton is ....
A
$1: 4$
B
$4: 1$
C
$2: 1$
D
$1: 2$
(JEE MAIN-2022)
Solution
$\frac{ R _{\alpha}}{ R _{ P }}=\frac{ M _{\alpha}}{ M _{ P }} \times \frac{ q _{ p }}{ q _{\alpha}}$
$\frac{ R _{\alpha}}{ R _{ p }}=\frac{4}{1} \times \frac{1}{2}=2$
Standard 12
Physics
