A car runs at a constant speed on a circular | vedclass

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Question

$\begin{array}{l}
{m{Distance}}\,travelled\,in\,one\,rotation\,\left( {lap} ight) = 2\pi r\
	herefore \,Average\,speed = \frac{{{m{distance}

Vedclass · Accepted Answer

$0 \,m/s ,10 \,m/s$

Vedclass · Answer

$\begin{array}{l}
{m{Distance}}\,travelled\,in\,one\,rotation\,\left( {lap} ight) = 2\pi r\
	herefore \,Average\,speed = \frac{{{m{distance}}}}{{time}} = \frac{{2\pi r}}{t}\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{2 	imes 3.14 	imes 100}}{{62.8}} = 10\,m\,{s^{ - 1}}\
Net\,displacement\,in\,one\,lap = 0\
Averagy\,velocity\, = \frac{{net\,displacement}}{{time}} = \frac{0}{t} = 0.
\end{array}$

A car runs at a constant speed on a circular track of radius $100\,m$ , taking $62.8\,sec$ for every circular lap. The average velocity and average speed for each circular lap respectively is

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