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11.Thermodynamics
normal
A Carnot engine operating between temperatures $T_1$ and $T_2$ has efficientcy $\frac{1}{6}$ . When $T_2$ is lowered by $62\,K$, its efficiency increases to $\frac{1}{3}$ . Then $T_1$ and $T_2$ are, respectively
A
$330\, K$ and $268\, K$
B
$310\, K$ and $248\, K$
C
$372\, K$ and $310\, K$
D
$372\, K$ and $330\, K$
Solution
$1-\frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}=\frac{1}{6}$
$1-\frac{\mathrm{T}_{2}-62}{\mathrm{T}_{1}}=\frac{1}{3}$
on solving $\mathrm{T}_{1}=372 \mathrm{K}, \mathrm{T}_{2}=310 \mathrm{K}$
Standard 11
Physics
