Volume of a gas is reduced adiabatically to (1/4)^{th} of its volume at 27,^oC . If gamma = 1.4 new

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11.Thermodynamics

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The volume of a gas is reduced adiabatically to $(1/4)^{th}$ of its volume at $27\,^oC$ . If $\gamma = 1.4$ the new temperature is

A

$(300)\,4^{0.4}\,K$

B

$(300)\,2^{0.4}\,K$

C

$300\,(4)^{1.4}\,K$

D

$(300)\,2^{1.4}\,K$

Solution

$\mathrm{TV}^{\gamma-1}=\mathrm{T}_{0} \mathrm{V}_{0}^{\gamma-1}$

$\mathrm{T}\left(\frac{\mathrm{v}_{0}}{4}\right)^{0.4}=\mathrm{T}_{0} \mathrm{V}_{0}^{0.4}$

$\left.\mathrm{T}=300 \times 4^{0.4}\right]$

Standard 11

Physics

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