A charge $Q\;\mu C$ is placed at the centre of a cube, the flux coming out from any surfaces will be
$\frac{Q}{8 \varepsilon_{0}}$
$\frac{Q}{24\varepsilon_{0}}$
$\frac{Q}{6 \varepsilon_{0}} \times 10^{-3}$
$\frac{Q}{6 \varepsilon_{0}} \times 10^{-6}$
How much electric flux will come out through a surface $S = 10\hat j$ kept in an electrostatic field $\vec E = 2\hat i + 4\hat j + 7\hat k$.........$units$
A rectangular surface of sides $10 \,cm$ and $15 \,cm$ is placed inside acyniform electric field of $25 \,V / m$, such that the surface makes an angle of $30^{\circ}$ with the direction of electric field. Find the flux of the electric field through the rectangular surface .................. $Nm ^2 / C$
Figure shows the electric lines of force emerging from a charged body. If the electric field at $A$ and $B$ are ${E_A}$ and ${E_B}$ respectively and if the displacement between $A$ and $B$ is $r$ then
A charge $q$ is surrounded by a closed surface consisting of an inverted cone of height $h$ and base radius $R$, and a hemisphere of radius $R$ as shown in the figure. The electric flux through the conical surface is $\frac{n q}{6 \epsilon_0}$ (in SI units). The value of $n$ is. . . .
How does the no. of electric field lines passing through unit area depend on distance ?